2x^2-61x+72=0

Solution for 2x^2-61x+72=0 equation:

2x^2-61x+72=0

a = 2; b = -61; c = +72;
Δ = b2-4ac
Δ = -612-4·2·72
Δ = 3145
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-61)-\sqrt{3145}}{2*2}=\frac{61-\sqrt{3145}}{4}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-61)+\sqrt{3145}}{2*2}=\frac{61+\sqrt{3145}}{4}
$